The probability of Anna passing her driving test is 0.7. Square Tes Global Ltd is Example: A bag contains 4 red balls and 5 blue balls. I Let H be the event that a heart is drawn, I let R be the event that a red card is drawn and \textcolor{black}{\text{P}(A \text{ given } B) = \text{P}(A)} \,\, \,\, \textcolor{black}{\text{P}(B \text{ given } A) = \text{P}(B)}, \text{P(blue and blue)}=\dfrac{5}{9}\times\dfrac{4}{8}= \textcolor{blue}{\dfrac{20}{72}}, \text{ and } \text{P(red and red)}=\dfrac{4}{9}\times\dfrac{3}{8}= \textcolor{red}{\dfrac{12}{72}}. Make sure you are happy with the following topics before continuing. About This Quiz & Worksheet. Calculate the probability the bus is late on each of those days. To work out the probability of Rob passing we can write the probability of both passing as: Substituting in the probability of Anna passing her test. A-Level Edexcel Statistics S1 June 2008 Q1d (Probability Tree diagrams) : ExamSolutions - youtube Video MichaelExamSolutionsKid 2020-02-25T15:02:58+00:00 About ExamSolutions We can see that there are two ways of doing this, either blue and blue, or red and red. Syntax Tree Diagram Exercises With Syntax tree diagrams 1. Picking a red marble at random from a bag, then picking a green marble without replacing the red marble are dependent events. 5. A girls' choir is choosing a uniform for their concert. Question 1 . 6 5 There are 5 red balls and 6 green balls in a bag. They can pick red, green, or purple sweaters, and they can pick tan, white, or black skirts. Adding together the … Recall that there are 13 hearts, 13 diamonds, 13 spades and 13 clubs in a standard deck of cards. The chance of selecting a red ball for the first selection is \dfrac{4}{9}, then with one red ball removed, the second selection is \dfrac{3}{8} and so on…. 4.8 56 customer reviews. A-Level Edexcel Statistics S1 June 2008 Q1d (Probability Tree diagrams) : ExamSolutions - youtube Video MichaelExamSolutionsKid 2020-02-25T15:02:58+00:00 About ExamSolutions (a) Let “Anna passing” be event A_p and “Rob” passing be event B_p. If two events, A and B, are independent, then, \textcolor{black}{\text{P}(A \text{ given } B) = \text{P}(A)} \,\, and \,\, \textcolor{black}{\text{P}(B \text{ given } A) = \text{P}(B)}, If two events, A and B are dependent, then, \textcolor{black}{\text{P}(A \text{ and } B) = \text{P}(A) \times \text{P}(B \text{ given } A)}. Then answer this question. Donʼt spend too long on one question. 5-a-day … About This Quiz & Worksheet. \text{P}(A \text{ or } B) = \text{P}(A) + \text{P}(B) - \text{P}(A \text{ and } B), \text{P}(A \text{ or } B) = \text{P}(A) + \text{P}(B). Conditional Probability and Tree Diagrams Example Let us consider the following experiment: A card is drawn at random from a standard deck of cards. If he starts the game, the probability that he scores a goal is 0.4. Calculate the probability that he selects the same coloured ball each time, given that each time a ball is selected, it is not replaced. Exam Style Questions Ensure you have: Pencil, pen, ruler, protractor, pair of compasses and eraser You may use tracing paper if needed Guidance 1. Draw a tree diagram in your math workbook. Check your answers seem right. 13 Questions Show answers. Here we have to work out the probability that the coach takes out two balls that are a different colour. (2)! We need to understand independent and dependent events to be able to do the next sections. 300 seconds . Tree diagrams are particularly useful when we have several possible outcomes and can help you record all the possibilities in a clear, uncomplicated manner. This means to find the probability of A and B occurring you must multiply the probability of A occurring by the probability of B occurring. Going along the bottom line we find that the probability of being late of both days is: Question 4: There are 14 footballs in a bag, 9 have a blue pattern design and the rest have green pattern design. The probability that he is in the starting line up for his team this Sunday is 0.7. (a) The resultant tree diagram should look something like: (b) To find the probability he wins at least one game we can simple add the top 3 branches probabilities together or subtract the probability of bottom branch from 1: \dfrac{9}{25}+\dfrac{6}{25}+\dfrac{6}{25}=\dfrac{21}{25}. Exam Style Questions Ensure you have: Pencil, pen, ruler, protractor, pair of compasses and eraser You may use tracing paper if needed Guidance 1. \text{P}(A \text{ and } B) = \text{P}(A) \times \text{P}(B). Preview. Complete the tree diagram. Draw a tree diagram in your math workbook. Practice Questions; Post navigation. registered in England (Company No 02017289) with its registered office at 26 Red Lion \text{P(blue and blue)}=\dfrac{5}{9}\times\dfrac{5}{9}= \textcolor{blue}{\dfrac{25}{81}} \,\, \,\, \text{P(red and red)}=\dfrac{4}{9}\times\dfrac{4}{9}= \textcolor{red}{\dfrac{16}{81}}. There are 9 balls to begin with, reducing to 8 after the first selection, as shown below. The probability of both Anna and Rob passing is 0.35. You must show your workings. Attempt every question.

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